Merge Intervals
Given a collection of intervals, merge all overlapping intervals.
For example,
Given
return
*/For example,
Given
[1,3],[2,6],[8,10],[15,18],return
[1,6],[8,10],[15,18]. /**
* Definition for an interval.
* struct Interval {
* int start;
* int end;
* Interval() : start(0), end(0) {}
* Interval(int s, int e) : start(s), end(e) {}
* };
*/
class Solution {
public:
void findIndex(vector<Interval> intervals, int & startPrevIndex, int num){
int size = intervals.size();
if(num<intervals[startPrevIndex].start) return;
while(startPrevIndex<size){
if(intervals[startPrevIndex].start <= num && (startPrevIndex == (size-1) || num < intervals[startPrevIndex+1].start)){
return;
}
startPrevIndex++;
}
}
void findEndIndex(vector<Interval> intervals, int & endPrevIndex, int num){
int size = intervals.size();
if(num<intervals[endPrevIndex].end) return;
while(endPrevIndex<size){
if(intervals[endPrevIndex].end <= num && (endPrevIndex == (size-1) || num < intervals[endPrevIndex+1].end)){
return;
}
endPrevIndex++;
}
}
vector<Interval> insert(vector<Interval> &intervals, Interval newInterval) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
if(newInterval.start > newInterval.end) return intervals;
int size = intervals.size();
if(size==0){
intervals.push_back(newInterval);
return intervals;
}
int start = newInterval.start;
int end = newInterval.end;
if(end < intervals[0].start){
intervals.insert(intervals.begin(), newInterval);
return intervals;
}
if(end == intervals[0].start){
intervals[0].start = newInterval.start;
return intervals;
}
if(start > intervals[size-1].end){
intervals.push_back(newInterval);
return intervals;
}
if(start == intervals[size-1].end){
intervals[size-1].end = newInterval.end;
return intervals;
}
int startPrevIndex = 0;
findIndex(intervals, startPrevIndex, start);
int endPrevIndex = 0;
findEndIndex(intervals, endPrevIndex, end);
if(start<intervals[startPrevIndex].end && end<=intervals[startPrevIndex].end){
if(startPrevIndex==0 && start<intervals[startPrevIndex].start){
intervals[startPrevIndex].start = start;
}
return intervals;
}
int i;
if(start<=intervals[startPrevIndex].end){
if(startPrevIndex==0 && start<intervals[startPrevIndex].start){
intervals[startPrevIndex].start = start;
}
i = startPrevIndex+1;
if(endPrevIndex==size-1){
while(i<=size-1){
intervals.erase(intervals.begin()+startPrevIndex+1);
i++;
}
intervals[startPrevIndex].end = end;
return intervals;
}
if(end<intervals[endPrevIndex+1].start){
intervals[startPrevIndex].end = end;
if(startPrevIndex==endPrevIndex) return intervals;
while(i<=endPrevIndex){
intervals.erase(intervals.begin()+startPrevIndex+1);
i++;
}
return intervals;
}
if(end>=intervals[endPrevIndex+1].start){
i = startPrevIndex+1;
intervals[startPrevIndex].end = intervals[endPrevIndex+1].end;
while(i<=(endPrevIndex+1)){
intervals.erase(intervals.begin()+startPrevIndex+1);
i++;
}
return intervals;
}
}
if(start>intervals[startPrevIndex].end && end<intervals[startPrevIndex+1].start){
intervals.insert(intervals.begin()+startPrevIndex+1, newInterval);
return intervals;
}
if(start>intervals[startPrevIndex].end){
intervals[startPrevIndex+1].start = start;
i = startPrevIndex+2;
if(endPrevIndex==size-1){
while(i<=size-1){
intervals.erase(intervals.begin()+startPrevIndex+2);
i++;
}
intervals[startPrevIndex+1].end = end;
return intervals;
}
if(end >= intervals[endPrevIndex+1].start){
intervals[startPrevIndex+1].end = intervals[endPrevIndex+1].end;
while(i<=(endPrevIndex+1)){
intervals.erase(intervals.begin()+startPrevIndex+2);
i++;
}
return intervals;
}
if(end < intervals[endPrevIndex+1].start){
while(i<=(endPrevIndex)){
intervals.erase(intervals.begin()+startPrevIndex+2);
i++;
}
intervals[startPrevIndex+1].end = end;
return intervals;
}
}
}
vector<Interval> merge(vector<Interval> &intervals) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int size = intervals.size();
if(size<=1) return intervals;
vector<Interval> result;
result.push_back(intervals[0]);
int i;
for(i=1; i<size; i++){
result = insert(result, intervals[i]);
}
return result;
}
};
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