Sum Root to Leaf Numbers
Given a binary tree containing digits from
An example is the root-to-leaf path
Find the total sum of all root-to-leaf numbers.
For example,
The root-to-leaf path
The root-to-leaf path
Return the sum = 12 + 13 =
*/0-9 only, each root-to-leaf path could represent a number.An example is the root-to-leaf path
1->2->3 which represents the number 123.Find the total sum of all root-to-leaf numbers.
For example,
1 / \ 2 3
The root-to-leaf path
1->2 represents the number 12.The root-to-leaf path
1->3 represents the number 13. Return the sum = 12 + 13 =
25. /**
* Definition for binary tree
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
void getSum(TreeNode *curr, int pathSum, int & sum){
if(curr == NULL){
return;
}
pathSum = pathSum*10 + curr->val;
if(curr->left==NULL && curr->right==NULL) sum = sum + pathSum;
getSum(curr->left, pathSum, sum);
getSum(curr->right, pathSum, sum);
}
int sumNumbers(TreeNode *root) {
// Start typing your C/C++ solution below
// DO NOT write int main() function
int pathSum = 0;
int sum = 0;
getSum(root,pathSum,sum);
return sum;
}
};
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